[py] Simplify 2015_03

This commit is contained in:
Joscha 2022-12-06 21:19:53 +01:00
parent f6198637a8
commit 18b58fd936
5 changed files with 15 additions and 39 deletions

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# PART 1 def santa(directions):
def find_doubles(steps):
x, y = 0, 0 x, y = 0, 0
houses = {(0, 0)} houses = {(0, 0)}
for step in steps: for d in directions:
if step == "^": dx, dy = {"^": (0, 1), "v": (0, -1), "<": (-1, 0), ">": (1, 0)}[d]
y += 1 x, y = x + dx, y + dy
elif step == "v":
y -= 1
elif step == "<":
x -= 1
elif step == ">":
x += 1
houses.add((x, y)) houses.add((x, y))
return houses return houses
# PART 2
def split_string(s):
s1 = ""
s2 = ""
while True:
if not s:
break
s1 += s[0]
s = s[1:]
if not s:
break
s2 += s[0]
s = s[1:]
return s1, s2
def solve(inputstr): def solve(inputstr):
steps = inputstr.strip() directions = inputstr.strip()
doubles = len(find_doubles(steps)) part1 = len(santa(directions))
print(f"Part 1: {doubles}") print(f"Part 1: {part1}")
santa, robot = split_string(steps) part2 = len(santa(directions[::2]) | santa(directions[1::2]))
santa_doubles = find_doubles(santa) print(f"Part 2: {part2}")
robot_doubles = find_doubles(robot)
doubles_2 = len(santa_doubles | robot_doubles)
print(f"Part 2: {doubles_2}")

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^>v<

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Part 1: 4
Part 2: 3

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^v^v^v^v^v

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Part 1: 2
Part 2: 11