[py] Port 2015_05
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3 changed files with 58 additions and 55 deletions
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@ -1,54 +0,0 @@
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import sys
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def load_words(filename):
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words = []
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with open(filename, "r") as f:
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for line in f:
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words.append(line[:-1])
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return words
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# PART 1
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def is_vowel(char):
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return char in "aeiou"
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def has_double_letter(word):
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# This would look nicer im haskell:
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return count(zip(word, word[1:]), lambda x: x[0] == x[1]) > 0
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def is_nice(word):
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if "ab" in word or "cd" in word or "pq" in word or "xy" in word:
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return False
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if len(list(filter(is_vowel, word))) < 3:
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return False
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return has_double_letter(word)
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def count(what, function):
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# This would also look nicer in haskell
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return len(list(filter(function, what)))
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# PART 2
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def has_pair(word):
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for i in range(len(word)):
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if word[i:i+2] in word[i+2:]:
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return True
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return False
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def has_repeat_letter(word):
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return count(zip(word, word[2:]), lambda x: x[0] == x[1]) > 0
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def is_nice_2(word):
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return has_pair(word) and has_repeat_letter(word)
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def main(filename):
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words = load_words(filename)
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print(f"Solutions for {filename}")
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amount = count(words, is_nice)
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print(f"Part 1: {amount}")
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amount_2 = count(words, is_nice_2)
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print(f"Part 2: {amount_2}")
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if __name__ == "__main__":
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for filename in sys.argv[1:]:
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main(filename)
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@ -2,7 +2,7 @@ import sys
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import argparse
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import argparse
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from pathlib import Path
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from pathlib import Path
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from .y2015 import d01, d02, d03, d04
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from .y2015 import d01, d02, d03, d04, d05
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from .y2016 import d01, d02, d03, d04, d05
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from .y2016 import d01, d02, d03, d04, d05
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from .y2017 import d01, d02, d03, d04, d05, d06, d07, d08, d09
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from .y2017 import d01, d02, d03, d04, d05, d06, d07, d08, d09
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from .y2018 import d01, d02, d03, d04, d05, d06, d07, d08, d09, d10, d11
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from .y2018 import d01, d02, d03, d04, d05, d06, d07, d08, d09, d10, d11
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@ -15,6 +15,7 @@ DAYS = {
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"2015_02": y2015.d02.solve,
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"2015_02": y2015.d02.solve,
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"2015_03": y2015.d03.solve,
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"2015_03": y2015.d03.solve,
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"2015_04": y2015.d04.solve,
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"2015_04": y2015.d04.solve,
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"2015_05": y2015.d05.solve,
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"2016_01": y2016.d01.solve,
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"2016_01": y2016.d01.solve,
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"2016_02": y2016.d02.solve,
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"2016_02": y2016.d02.solve,
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"2016_03": y2016.d03.solve,
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"2016_03": y2016.d03.solve,
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56
py/aoc/y2015/d05.py
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56
py/aoc/y2015/d05.py
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@ -0,0 +1,56 @@
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def load_words(inputstr):
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words = []
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for line in inputstr.splitlines():
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words.append(line)
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return words
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# PART 1
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def is_vowel(char):
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return char in "aeiou"
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def has_double_letter(word):
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# This would look nicer im haskell:
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return count(zip(word, word[1:]), lambda x: x[0] == x[1]) > 0
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def is_nice(word):
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if "ab" in word or "cd" in word or "pq" in word or "xy" in word:
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return False
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if len(list(filter(is_vowel, word))) < 3:
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return False
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return has_double_letter(word)
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def count(what, function):
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# This would also look nicer in haskell
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return len(list(filter(function, what)))
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# PART 2
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def has_pair(word):
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for i in range(len(word)):
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if word[i : i + 2] in word[i + 2 :]:
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return True
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return False
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def has_repeat_letter(word):
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return count(zip(word, word[2:]), lambda x: x[0] == x[1]) > 0
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def is_nice_2(word):
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return has_pair(word) and has_repeat_letter(word)
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def solve(inputstr):
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words = load_words(inputstr)
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amount = count(words, is_nice)
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print(f"Part 1: {amount}")
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amount_2 = count(words, is_nice_2)
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print(f"Part 2: {amount_2}")
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